c# – Method Overloading: Have two or methods of the same name

Method Overloading is basically a technique that lets you have different versions of the same method, where each version of the method does a different thing.

It essentially makes methods more versatile.

Each version of the method accepts different/types of input parameters.

The way you control which of version method you want to trigger, is by specifying the correct number/type of input parameters for that corresponding method.

In the following example, we have 2 methods, which in this case achieves the same goal by different means. The here is to instantiate an object:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

class Employee
    public string Firstname { get; set; }
    public int Age { get; set; }
    public double Salary { get; set; }

	// we are going to use a technique called method overloading
	// as a way to have 2 methods of the same name, 
	// and leave it to c# to work out which method we want based 
	// on the input parameter provided when the method is called. 

    public Employee(string firstname, int age, double salary)
        Firstname = firstname;
        Age = age;
        Salary = salary;

    public Employee()
    { }

class Program
    static void Main()
		// Here we initialised the object using the 
		//default constructor
		// to create the empty memory container.
		Employee Dave = new Employee()
            Firstname = "David",
            Age = 35,
            Salary = 35235.23
        Console.WriteLine("{0} is {1} years old and earns  £{2} per year.", Dave.Firstname, Dave.Age.ToString(), Dave.Salary.ToString());

		// Here we used the constructor to create
        Employee Jenny = new Employee("Jennifer", 22, 25023.50);
		Console.WriteLine("{0} is {1} years old and earns  £{2} per year.", Jenny.Firstname, Jenny.Age.ToString(), Jenny.Salary.ToString());